Optimal. Leaf size=77 \[ \frac {\sqrt [4]{\cos ^2(a+b x)} \, _2F_1\left (\frac {1}{4},\frac {1+m}{2};\frac {3+m}{2};\sin ^2(a+b x)\right ) \sqrt {d \sec (a+b x)} (c \sin (a+b x))^{1+m}}{b c d (1+m)} \]
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Rubi [A]
time = 0.07, antiderivative size = 77, normalized size of antiderivative = 1.00, number of steps
used = 2, number of rules used = 2, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.087, Rules used = {2666, 2657}
\begin {gather*} \frac {\sqrt [4]{\cos ^2(a+b x)} \sqrt {d \sec (a+b x)} (c \sin (a+b x))^{m+1} \, _2F_1\left (\frac {1}{4},\frac {m+1}{2};\frac {m+3}{2};\sin ^2(a+b x)\right )}{b c d (m+1)} \end {gather*}
Antiderivative was successfully verified.
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Rule 2657
Rule 2666
Rubi steps
\begin {align*} \int \frac {(c \sin (a+b x))^m}{\sqrt {d \sec (a+b x)}} \, dx &=\frac {\left (\sqrt {d \cos (a+b x)} \sqrt {d \sec (a+b x)}\right ) \int \sqrt {d \cos (a+b x)} (c \sin (a+b x))^m \, dx}{d^2}\\ &=\frac {\sqrt [4]{\cos ^2(a+b x)} \, _2F_1\left (\frac {1}{4},\frac {1+m}{2};\frac {3+m}{2};\sin ^2(a+b x)\right ) \sqrt {d \sec (a+b x)} (c \sin (a+b x))^{1+m}}{b c d (1+m)}\\ \end {align*}
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Mathematica [C] Result contains higher order function than in optimal. Order 6 vs. order 5 in
optimal.
time = 18.67, size = 289, normalized size = 3.75 \begin {gather*} \frac {8 c (3+m) F_1\left (\frac {1+m}{2};-\frac {1}{2},\frac {3}{2}+m;\frac {3+m}{2};\tan ^2\left (\frac {1}{2} (a+b x)\right ),-\tan ^2\left (\frac {1}{2} (a+b x)\right )\right ) \cos ^4\left (\frac {1}{2} (a+b x)\right ) \sin ^2\left (\frac {1}{2} (a+b x)\right ) (c \sin (a+b x))^{-1+m}}{b (1+m) \left (\left ((3+2 m) F_1\left (\frac {3+m}{2};-\frac {1}{2},\frac {5}{2}+m;\frac {5+m}{2};\tan ^2\left (\frac {1}{2} (a+b x)\right ),-\tan ^2\left (\frac {1}{2} (a+b x)\right )\right )+F_1\left (\frac {3+m}{2};\frac {1}{2},\frac {3}{2}+m;\frac {5+m}{2};\tan ^2\left (\frac {1}{2} (a+b x)\right ),-\tan ^2\left (\frac {1}{2} (a+b x)\right )\right )\right ) (-1+\cos (a+b x))+(3+m) F_1\left (\frac {1+m}{2};-\frac {1}{2},\frac {3}{2}+m;\frac {3+m}{2};\tan ^2\left (\frac {1}{2} (a+b x)\right ),-\tan ^2\left (\frac {1}{2} (a+b x)\right )\right ) (1+\cos (a+b x))\right ) \sqrt {d \sec (a+b x)}} \end {gather*}
Warning: Unable to verify antiderivative.
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Maple [F]
time = 0.12, size = 0, normalized size = 0.00 \[\int \frac {\left (c \sin \left (b x +a \right )\right )^{m}}{\sqrt {d \sec \left (b x +a \right )}}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (c \sin {\left (a + b x \right )}\right )^{m}}{\sqrt {d \sec {\left (a + b x \right )}}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\left (c\,\sin \left (a+b\,x\right )\right )}^m}{\sqrt {\frac {d}{\cos \left (a+b\,x\right )}}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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